you can work these sorts of things out pretty easily with some simple math.
ok, your dual 4ohm coils with a single woofer:
in Series __0______0___
you have 4ohms + 4ohms
=8ohm load on the amp.
in Parrallel
___0___
|__0___|
You have 4ohms / 2 coils
= 2ohm load on the amp.
then you can combine these if you have 2 woofers.
two woofers with their coils in series and the woofer in series = 8ohms + 8 ohms = 16 ohm load on amp
two woofers with coils in parrallel and woofers in series = 2ohms + 2ohms = 4 ohm load
two woofers with coils in series and woofers in parrallel = 8 ohms / 2 woofers = 4 ohm load
two woofers with coils in parrallel and woofers in parrallel = 2ohms / 2 woofers = 1 ohm load.
easy huh.
Series adds the impedance.
parralel divides it by the number of loads i the chain.
ok, your dual 4ohm coils with a single woofer:
in Series __0______0___
you have 4ohms + 4ohms
=8ohm load on the amp.
in Parrallel
___0___
|__0___|
You have 4ohms / 2 coils
= 2ohm load on the amp.
then you can combine these if you have 2 woofers.
two woofers with their coils in series and the woofer in series = 8ohms + 8 ohms = 16 ohm load on amp
two woofers with coils in parrallel and woofers in series = 2ohms + 2ohms = 4 ohm load
two woofers with coils in series and woofers in parrallel = 8 ohms / 2 woofers = 4 ohm load
two woofers with coils in parrallel and woofers in parrallel = 2ohms / 2 woofers = 1 ohm load.
easy huh.
Series adds the impedance.
parralel divides it by the number of loads i the chain.